Answer:
Problem #1 : 21.2 %
Problem #2 : 20g of glucose
Explanation:
Problem 1: mass solution = mass solute + mass solvent
mass solution = 5.30 g + 19.7 g
mass solution = 25.0 g
percent by mass = (mass solute / mass solution) × 100
percent by mass = (5.30 g / 25.0 g) × 100
percent by mass = 21.2%
Problem #2 :
xg / 400 = 0.05g / m * L
xg = (400mL)(0.05g / m * L)
x g = (400ml)(5g / 100mL)
x = 20g
xg / 400 = 0.05g / m * L
xg = (400mL)(0.05g / m * L)
x g = (400ml)(5g / 100mL)
x = 20g
