Answer:
18.42 grams
Explanation:
The given are Molarity of 1.842M NaOH and total volume of solution of 250 mL.
Step 1: We know that Molarity = [tex]\frac{moles of solute}{liters of solution}[/tex]
Hence:
1.842 M = [tex]\frac{moles of solute (NaOH)}{250 mL}[/tex]
Step 2: To avoid unit discrepancy, first convert the total volume of solution from mL to L. We know that 1000mL is 1 L. Hence:
Liters of solution = 250 mL x [tex]\frac{1 Liter}{1000 mL}[/tex] = 0.25 Liter
Step 3: Going back to our original equation, we will get the moles of solute:
1.842 M = [tex]\frac{moles of solute}{0.25 L}[/tex]
moles of solute = 1.842 M x 0.25 L = 0.4605 moles of NaOH.
Step 4: To get the mass of NaOH required, we will use the molecular weight of NaOH of 39.997 grams per mole. Therefore:
0.4605 moles of NaOH x [tex]\frac{39.997 grams NaOH}{moles of NaOH}[/tex] = 18.42 grams of NaOH.
18.42 grams of NaOH must be used to make 250 mL of a 1.842 M solution of NaOH.
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