Answered

find three consecutive integers such that three times the first,plus twice the second,plus the third equals 166

Sagot :

Juameviz
let x be the first integer
x+1 be the second
and x+2 be the third.

3(x)+2(x+1)+x+2=166
3x+ 2x+2+x+2=166
3x+2x+x=166-2-2
6x=162
divide both by 6
6x/6=x
162/6=27

x=27 the first integer
x+1= 27+1
28 be the second
x+2=
29 be the third integer

answer
27,28,29