Answered

1. What is the magnitude of the Centripetal Force that must be applied in order for a 2.50 kg ball on a 4.0m string to spin with uniform circular motion at 5.0m/s? pls. asap lng Po ​

Sagot :

Tokamakviz

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The centripetal force exerted on an object is given by

[tex]\boxed{F_{c} = \frac{mv^{2}}{r}}[/tex]

where:

[tex]F_{c} =[/tex] centripetal force

m = mass

v = velocity

r = radius

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for the centripetal force

[tex]F_{c} = \dfrac{mv^{2}}{r}[/tex]

[tex]F_{c} = \dfrac{(\text{2.50 kg})(\text{5.0 m/s})^{2}}{\text{4.0 m}}[/tex]

[tex]\boxed{F_{c} = \text{15.625 N}}[/tex]

Therefore, the magnitude of the centripetal force is 15.625 N.

[tex]\\[/tex]

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