what is the standard form of the quadratic equation (r-7)(r+)=0


Sagot :

Answer:

r =(1+√197)/14= 1.074

or:

r =(1-√197)/14=-0.931

Step-by-step explanation:

Step 1 :Equation at the end of step 1

(7r2 - r) - 7 = 0

Step 2:Trying to factor by splitting the middle term

2.1 Factoring 7r2-r-7

2.1 Factoring 7r2-r-7 The first term is, 7r2 its coefficient is 7 .

2.1 Factoring 7r2-r-7 The first term is, 7r2 its coefficient is 7 .The middle term is, -r its coefficient is -1 .

2.1 Factoring 7r2-r-7 The first term is, 7r2 its coefficient is 7 .The middle term is, -r its coefficient is -1 .The last term, "the constant", is -7

2.1 Factoring 7r2-r-7 The first term is, 7r2 its coefficient is 7 .The middle term is, -r its coefficient is -1 .The last term, "the constant", is -7 Step-1 : Multiply the coefficient of the first term by the constant 7 • -7 = -49

2.1 Factoring 7r2-r-7 The first term is, 7r2 its coefficient is 7 .The middle term is, -r its coefficient is -1 .The last term, "the constant", is -7 Step-1 : Multiply the coefficient of the first term by the constant 7 • -7 = -49 Step-2 : Find two factors of -49 whose sum equals the coefficient of the middle term, which is -1 .

-49 + 1 = -48

-49 + 1 = -48 -7 + 7 = 0

-49 + 1 = -48 -7 + 7 = 0 -1 + 49 = 48

Observation : No two such factors can be found !!

Observation : No two such factors can be found !!Conclusion : Trinomial can not be factored

Equation at the end of step

Equation at the end of step2