Answer:
ײ-10×+34=0
Step-by-step explanation:
let xi=5+3i x²= 5-3i to
(x-xi) (x-x²=0
so [x(5+3i) (x-5+3i) =0
so x²-5×+3i× -5×+25-15i -3i×+
15i-9i²=0
so the answer isײ-20×+34=0
correct me if I'm wrong..btw hope it's help
GANAN DIN MODULE NG KAPATID KO..