Answered

3. Evaluate the function h(x) = 3x3 + x2 - 12 for x = 3;​

Sagot :

Answer:

h(3)=88

Substitute 3

h(3)=3(3)³+(3)²-12

h(3)=3(27)+9-12

h(3)=81+9-12

h(3)=90-12

h(3)=88

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Answer:

h(x)= 3x^3+x^2-12

h(3)=3(3)^3+3^2-12

h(3)=3(27)+9-12

h(3)=81+(-3)

h(3)=78

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