Viang1750viz
Answered


[tex] \sqrt{x + 2 = x} [/tex]
[tex]x + \frac{6}{x} + 5 = 0[/tex]
[tex] \frac{2}{x + 2} + \frac{3}{x - 3} = - \frac{5}{6} [/tex]
[tex] \frac{1}{x ^{2} } - \frac{3}{x} + 2 = 0[/tex]
[tex]x - 7 \sqrt{x \: } + 6 = 0[/tex]
wjdjdj​

Sagot :

Elciaejeanneviz

Answer:

\sqrt{x + 2 = x}

x+2=x

x + \frac{6}{x} + 5 = 0x+

x

6

+5=0

\frac{2}{x + 2} + \frac{3}{x - 3} = - \frac{5}{6}

x+2

2

+

x−3

3

=−

6

5

\frac{1}{x ^{2} } - \frac{3}{x} + 2 = 0

x

2

1

−

x

3

+2=0

x - 7 \sqrt{x \: } + 6 = 0x−7

x

+6=0

wjdjdj