Answer:
The percent by mass : 6.25%
Further explanation
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
So the concentration of a solution can be expressed as a percent which is the ratio of solute to solution. Can be expressed in percent of mass (m / m) or volume percent (v / v)
\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%%mass=
mass solution
mass solute
×100%
Solution = Solute + Solvent
The solute is the substance that is dissolved usually in smaller amounts when compared to solvents
Given
mass solute = mass of iron (II) sulfate-FeSO₄ = 5 g
mass solvent = mass of water-H₂O = 75 g
mass solution = mass solute + mass solvent
mass solution = 5 + 75 =80 g
Required
The percent by mass
Solution
Input the value :
\begin{gathered}\tt \%mass=\dfrac{5}{80}\times 100\%\\\\\%mass=6.25\%\end{gathered}
%mass=
80
5
×100%
%mass=6.25%
Explanation:
The percent by mass : 6.25%
Further explanation
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
So the concentration of a solution can be expressed as a percent which is the ratio of solute to solution. Can be expressed in percent of mass (m / m) or volume percent (v / v)
\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%%mass=
mass solution
mass solute
×100%
Solution = Solute + Solvent
The solute is the substance that is dissolved usually in smaller amounts when compared to solvents
Given
mass solute = mass of iron (II) sulfate-FeSO₄ = 5 g
mass solvent = mass of water-H₂O = 75 g
mass solution = mass solute + mass solvent
mass solution = 5 + 75 =80 g
Required
The percent by mass
Solution
Input the value :
\begin{gathered}\tt \%mass=\dfrac{5}{80}\times 100\%\\\\\%mass=6.25\%\end{gathered}
%mass=
80
5
×100%
%mass=6.25%
The percent by mass : 6.25%
Further explanation
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
So the concentration of a solution can be expressed as a percent which is the ratio of solute to solution. Can be expressed in percent of mass (m / m) or volume percent (v / v)
\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%%mass=
mass solution
mass solute
×100%
Solution = Solute + Solvent
The solute is the substance that is dissolved usually in smaller amounts when compared to solvents
Given
mass solute = mass of iron (II) sulfate-FeSO₄ = 5 g
mass solvent = mass of water-H₂O = 75 g
mass solution = mass solute + mass solvent
mass solution = 5 + 75 =80 g
Required
The percent by mass
Solution
Input the value :
\begin{gathered}\tt \%mass=\dfrac{5}{80}\times 100\%\\\\\%mass=6.25\%\end{gathered}
%mass=
80
5
×100%
%mass=6.25%
