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How many different numbers can be formed by rearranging the digits of 858,585,555?

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Formula : P = n!/ n! m! ...
Given  : n1 = 8 = 3
             n2 = 5 = 6
            n = 9
Solution : P = n! / n1! n2 ! = 9 !/ 3! 6 ! = 362,880/ (6)(720)
                                                        = 362,880/4,320
                                                        = 84      

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