solve by the quadratic formula 5X2+0.3X-.2=0

Sagot :

Given : 5x^2 + 0.3 x - .2 = 0
            a = 5 , b = 0.3 , c = -0.2
Using quadratic formula :
           x = -b plus and minus square root of 0.3^2 - 4 ( 5 ) ( - 0.2 ) / 2 ( 5 )
           x = - 5 plus and minus square root of 0.09 + 4 / 10
           x1 = - 0.3 + 2.02 / 10 = 0.172
           x2 = -0.3 - 2.02 / 10 = 0.232