The area of a rectangular room is 65m2. Find the perimeter of the room given that its length is 3m more than thrice its width.
Using quadratic equation


Sagot :

Length = 3w + 3, width = w

The area of a rectangle is length * width so:
65 = (3w+3)w
65 = 3w² + 3w
0 = 3w² + 3w - 65
We use the quadratic formula
w = -3 ± √[3²+4(3)(65)] = -3 ± √[9+780] = -3 ± √789
                  6                         6                  6
We only get the positive value.

Perimeter = 2(length + width)
Length = 3 (-3 + √789) + 3 = -3 + √789 + 3 = 3 + √789
                        6                      2                      2

Perimeter = 2 (  3 + √789 + -3 + √789 ) = 2 ( 9 + 3√789 -3 + √789 )
                              2              6                              6
6 + 4√789   m
         3