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what is the integral of cos^2 2x dx

Sagot :

Hisrennalp21viz
∫cos^2 2x dx

formula:
case III
cos^2 x dx = (1/2 - cos2x/2) dx

=∫(1/2 - cos (2)(2x)/2) dx
=(1/2)∫dx - (1/2)∫cos4x dx
                 where :
               (1/2)(1/4)∫cos4x 4dx

=1/2 x - 1/8 sin4x + C