The sum of three number is 81. The second number is twice the first number,and the third number is three less than four times the first number .find the number
Let x be the 1st number 2x the 2nd number 4x-3 the 3rd number x + 2x + 4x -3 =81 7x = 81 + 3 7x = 84 7 7 x = 12 Therefore 12 is the 1st number, 2(12) = 24 is the 2nd number, 4(12) - 3 = 45 is the 3rd number.
