Answer:
Initial velocity of car = 60 m/s = u
Final velocity = 0 = v
Distance covered = 360 m = S
Acceleration (or in this case deceleration) = a
v^2 - u^2 = 2aS
0 - (60) = 2a x 360
-3600 = 720a
-3600/720 = a
therefore, a = -5 m/s^2
Therefore the deceleration of the car is -5 m/s^2.
