the product of two consecutive integers is 7 more than the third consecutive integer. find/type the three consecutive positive integers in order.

Sagot :

Answer:

3, 4, and 5

Step-by-step explanation:

Step-by-step explanation:

Answer:

3 = 1ST POSITIVE INTEGER

4 = 2ND POSITIVE INTEGER

5 = 3RD POSITIVE INTEGER

Step-by-step explanation:

Let:

A = 1st integer,

B = 2nd integer or (A+1), and

C = 3rd integer or (A+2)

Therefore:

(A)(A+1) = (A+2)+7

A²+A = A+9

A²+A-A = 9

A² = 9

√A² = √9

A = 3

B = (A+1) = (3+1) = 4

C = (A+2) = (3+2) = 5

Checking:

(A)(B) = (C+7)

(3)(4) = (5+7)

12 = 12

Hope it helps.

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