Answered

Activity 3- Let's Do The Math!
Direction: Use Newton's second law equation to solve for force, mass, and acceleration,
Problem 1- A ball with a mass of 0.5 kg is hit with a force of 2.5N. What is its acceleration?
Problem 2- What is the acceleration of a 15kg box that is pushed across a horizontal surface
with a force of 50N?
Problem 3- An object with a mass of 2.0 kg has a force of 5.0 N applied to it. What is the
resulting acceleration of the object?
Problem 4- An object with a mass of 3.0 kg accelerates 2.5 m/s2 when an unknown force is
applied to it. What is the amount of the force?
Problem 5- An object accelerates 12.0 m/s?when a force of 6.0 N is applied to it. What is
the mass of the object?​

Sagot :

Tokamakviz

Problem 1:

Given:

m = 0.5 kg

F = 2.5 N

Required:

a

Solution:

F = ma

[tex]\dfrac{F}{m} = \dfrac{ma}{m}[/tex]

[tex]a = \dfrac{F}{m}[/tex]

[tex]a = \dfrac{\text{2.5 N}}{\text{0.5 kg}}[/tex]

[tex]\boxed{a = \text{5 m/}\text{s}^{2}}[/tex]

-----------------------------------------------------------

Problem 2:

Given:

m = 15 kg

F = 50 N

Required:

a

Solution:

F = ma

[tex]\dfrac{F}{m} = \dfrac{ma}{m}[/tex]

[tex]a = \dfrac{F}{m}[/tex]

[tex]a = \dfrac{\text{50 N}}{\text{15 kg}}[/tex]

[tex]\boxed{a = \text{3.33 m/}\text{s}^{2}}[/tex]

-----------------------------------------------------------

Problem 3:

Given:

m = 2.0 kg

F = 5.0 N

Required:

a

Solution:

F = ma

[tex]\dfrac{F}{m} = \dfrac{ma}{m}[/tex]

[tex]a = \dfrac{F}{m}[/tex]

[tex]a = \dfrac{\text{5.0 N}}{\text{2.0 kg}}[/tex]

[tex]\boxed{a = \text{2.5 m/}\text{s}^{2}}[/tex]

-----------------------------------------------------------

Problem 4:

Given:

m = 3.0 kg

a = 2.5 m/s²

Required:

F

Solution:

F = ma

F = (3.0 kg)(2.5 m/s²)

[tex]\boxed{F = \text{7.5 N}}[/tex]

-----------------------------------------------------------

Problem 5:

Given:

a = 12.0 m/s²

F = 6.0 N

Required:

m

Solution:

F = ma

[tex]\dfrac{F}{a} = \dfrac{ma}{a}[/tex]

[tex]m = \dfrac{F}{a}[/tex]

[tex]m = \dfrac{\text{6.0 N}}{\text{12.0 m/}\text{s}^{2}}[/tex]

[tex]\boxed{m = \text{0.50 kg}}[/tex]

[tex]\\[/tex]

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