Answered

At 28°C, a gas cylinder containing H has internal volume and pressure of 46.6L and 1.50x10^2 ATM. The gas escaped the cylinder and expand until the pressure reaches 1.00 ATM. If the temp. of the gas remains constant, what volume will the gas occupy?

Sagot :

Answer:

V = 6990 L or 6.99x10^3 L

Explanation:

Initial Pressure = 1.5x10^2 atm or 150 atm

Initial Volume = 46.6L

Initial Temperature = 28 C (28 + 273.15 = 301.15 K)

Final Pressure = 1 atm

Final Volume = ?

Initial Temperature = 28 C (28 + 273.15 = 301.15 K)

Formula:

Pi (Vi) / Ti = Pf (Vf) / Tf

150(46.6) / 301.15  =  1 (Vf) / 301.15

23.21102441  =  1 (Vf) / 301.15

then cross multiply

23.21102441(301.15) / 1  =  Vf

Vf = 6990 L or 6.99x10^3 L