[tex]\tt{\huge{\blue{Explanation:}}}[/tex]
The power of an object exerting a force F at a velocity v is given by
[tex]\boxed{P = Fv}[/tex]
where:
P = power
F = force
v = velocity
[tex]\tt{\huge{\red{Solution:}}}[/tex]
Solving for P
P = Fv
P = (28.809 N)(1067 m/s)
[tex]\boxed{P = \text{30,739.203 W}}[/tex]
Therefore, the power of the 0.408 LAPUA is 30,739.203 W.
[tex]\\[/tex]
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