QUIZ#01 PROBLEM SOLVING. Solve the following problems and show your solution and answer at the back of your paper. (identifying the given=1pts, formula=1 pts, solution with correct answer=3pts)
1. Saitama's toy car has the mass of 10kg is moving at a velocity of 20m/s? Compute its kinetic energy?
2. The papaya fruit has the mass of 6kg hanged on its tree with 3m from the ground. What is its potential energy?
3. A backhoe loader carried a sand load of 2000kg with a distance of 10 m in 60 seconds at constant velocity. How much the power of backhoe loader used?
4. In studio, the singer is audible because the temperature is 26°C. What is the speed of sound with the 26°C that makes the singer audible?
5. Compute the speed of sound at temperature of 29°C.



plsss po pakisagot. thank you​


Sagot :

Problem 1:

Given:

m = 10 kg

v = 20 m/s

Required:

KE

Solution:

[tex]KE = \dfrac{1}{2}mv^{2}[/tex]

[tex]KE = \dfrac{1}{2}(\text{10 kg})(\text{20 m/s})^{2}[/tex]

[tex]\boxed{KE = \text{2,000 J}}[/tex]

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Problem 2:

Given:

m = 6 kg

h = 3 m

Required:

PE

Solution:

PE = mgh

PE = (6 kg)(9.8 m/s²)(3 m)

[tex]\boxed{PE = \text{176.4 J}}[/tex]

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Problem 3:

Given:

m = 2,000 kg

d = 10 m

t = 60 s

Required:

P

Solution:

Solving for F

F = weight = mg

F = (2,000 kg)(9.8 m/s²)

F = 19,600 N

Solving for W

W = Fd

W = (19,600 N)(10 m)

W = 196,000 J

Solving for P

[tex]P = \dfrac{W}{t}[/tex]

[tex]P = \dfrac{\text{196,000 J}}{\text{60 s}}[/tex]

[tex]\boxed{P = \text{3,266.67 W}}[/tex]

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Problem 4:

Given:

T = 26°C

Required:

v

Solution:

v = 331 + 0.6T

v = 331 + 0.6(26)

[tex]\boxed{v = \text{346.6 m/s}}[/tex]

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Problem 5:

Given:

T = 29°C

Required:

v

Solution:

v = 331 + 0.6T

v = 331 + 0.6(29)

[tex]\boxed{v = \text{348.4 m/s}}[/tex]

[tex]\\[/tex]

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