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A 70 kg child climbs a 10 m long slide that is inclined at 30o with the horizontal. What is the potential energy of the child with respect to the ground?

Sagot :

Isekaijinviz

Answer:

PE = mgh = mg(L sinθ)

m = 75 kg

g = 9.8 m/s2

L = 6.00 m

θ = 30°

PE = (75)(9.8)(6.00 sin30°) kg m/s2 = 2205 joules

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