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Find the roots of the following quadratic equations.

1. 3x² + 2 = 5
2. x² + 9x + 14 = 0
3. x² - 2x + 1 = 0
4. 4x² - 4x = -1
5. x² - 5x + 6 = 0​


Sagot :

Answer:

1.

3x^2+2=5

3x^2+2-5=0

3x^2-3=0

3x^2=3

x^2=1

x=±[tex]\sqrt{1}[/tex]

 = 1 OR -1 (Both 1^2 and -1^2 lead to 1)

2.

x^2+9x+14=0

(x+2)(x+7)=0

x+2=0 OR x+7=0

x=-2 OR x=-7

3.

x^2-2x+1=0

(x-1)(x-1)=0 (Factorise by algebraic identity= a^2-2ab+b^2, which is (a-b)^2)

x-1=0

x=1

4.

4x^2-4x=-1

4x^2-4x+1=0

(2x−1)(2x−1)=0 (Factorise by algebraic identity= a^2-2ab+b^2, which is (a-b)^2)

2x-1=0

2x=1

x=1/2

5.

x^2-5x+6=0

(x−2)(x−3)=0 (Factorise by algebraic identity= a^2-2ab+b^2, which is (a-b)^2)

x-2=0 OR x-3=0

x=2 OR x=3

*NOTE*: Quadratic equations follow this format -> ax^2+bx+c, where a≠0 and x is the unknown

Hope this helped! :>