Write the first six terms of the sequence : an=3 + 2n


Sagot :

[tex]\large\underline{ \mathcal {SOLUTION}}:[/tex]

substitute 1,2,3,4,5,6 to the sequence

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a(n) = 3 + 2n

a(1) = 3 + 2(1)

a(1) = 3 + 2

a(1) = 5

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a(n) = 3 + 2n

a(2) = 3 + 2(2)

a(2) = 3 + 4

a(2) = 7

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a(n) = 3 + 2n

a(3) = 3 + 2(3)

a(3) = 3 + 6

a(3) = 9

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a(n) = 3 + 2n

a(4) = 3 + 2(4)

a(4) = 3 + 8

a(4) = 11

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a(n) = 3 + 2n

a(5) = 3 + 2(5)

a(5) = 3 + 10

a(5) = 13

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a(6) = 3 + 2n

a(6) = 3 + 2(6)

a(6) = 3 + 12

a(6) = 15

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[tex]\large\underline{ \mathcal {ANSWER}}:[/tex]

  • 5,7,9,11,13,15