Markkviz
Answered

find the ten terms of the arithmetic sequence where
3,6,9......

Sagot :

Formula: an= a1+(n-1) d

a10 =3 + (10-1) 3
 =3 + (9) 3
= 3+ (27)
=30
3,6,9,12,15,18,21,24,27,30