✏️ANSWER
[tex] 1)\frac{7}{12} [/tex]
[tex]2) \frac{3}{13} [/tex]
[tex]3) \frac{1}{4} [/tex]
✏️SOLUTION
all posible outcome are shown in table below.
➣1➣➣2➣➣3➣➣4➣➣➣5➣➣6➣
1 (1, 1) (1, 2) (1, 3) (1, 4) (,1, 5) (1, 6)
2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
5 (5, 1) (5, 2) (5, 3) (5,4) (5, 5) (,5, 6)
6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
all posible events: 6×6
two dice is not 8 events: 6+5+4+3+2+1
[tex]p1 = \frac{5 + 4 + 3 + 2 + 1}{6 \times 6} [/tex]
[tex]p1 = \frac{21}{6 \times 6} = \frac{21}{36} [/tex]
[tex] p1= \frac{7}{12} [/tex]
{SIMPLIFIED CALCULATION}
__________________________
2) {Poker in face poker a total of 12}
[tex]p2 = \frac{12}{52} [/tex]
[tex]p2 = \frac{3}{13} [/tex]
{IT PROBABILITY DEFINITION}
_________________________
3) All events are shown in below
(green, green)
(green, red)
(red, green)
(red, red)
[tex]p3 = \frac{1}{4} [/tex]
{BY PROBABILITY DEFINITION}
