Answer:
1) 2x²+4= x=0 and x=0
2) x²+2x= x=0 and x=-2
3) 4x²+8x= x=0 and x=-2
4) x²+2x+1= x=-1 and x=-1
5) x²+5x+6= x=-2 and x=-3
Solution:
#USING ANY METHOD OF A QUADRATIC EQUATION
#USING QUADRATIC FORMULA
1)
2x+4
a=0 b=2 c=4
x=-b±√b²-4ac/2a
x=-2±√(2)²-4(0)(4)/2(0)
x=-2±√(4)-0/0
x=-2±√4/0
x=-2±2/0
x=-2+2/0
x=0/0
x=0
x=-2-2/0
x=-4/0
x=0
#The roots of 2x+4 are 0 and 0#
#USING QUADRATIC FORMULA
2)
x²+2x
a=1 b=2 c=0
x=-b±√b²-4ac/2a
x=-2±√(2)²-4(1)(0)/2(1)
x=-2±√(4)-0)/2
x=-2±√4/2
x=-2±2/2
x=-2+2/2
x=0/2
x=0
x=-2-2/2
x=-4/2
x=-2
#The roots of x²+2x are 0 and -2#
#USING QUADRATIC FORMULA
3) 4x²+8x=
a=4 b=8 c=0
x=-b±√b²-4ac/2a
x=-8±√(8)²-4(4)(0)/2(4)
x=-8±√(64-0)/8
x=-8±√64/8
x=-8±8/8
x=-8+8/8
x=0/8
x=0
x=-8-8/8
x=-16/8
x=-2
#The roots of 4x²+8x are 0 and -2#
4)
#USING BY FACTORING
x²+2x+1=
(x+1) (x+1)=0
x²+1x+1x+1=0
x²+2x+1=0
(x+1) (x+1)=0
(x+1)=0 (x+1)=0
x=-1 x=-1
#The roots of x²+2x+1 are -1 and -1#
#USING QUADRATIC FORMULA
x²+2x+1
a=1 b=2 c=1
x=-b±√b²-4ac/2a
x=-2±√(2)²-4(1)(1)/2(1)
x=-2±√(4)-4/2
x=-2±√0/2
x=-2±0/2
x=-2+0/2
x=-2/2
x=-1
x=-2-0/2
x=-2/2
x=-1
#The roots of x²+2x+1 are -1 and -1#
5)
#USING BY FACTORING
(x+2) (x+3)=0
x²+3x+2x+6=0
x²+5x+6=0
(x+2) (x+3)=0
(x+2)=0 (x+3)=0
x=-2 x=-3
#The roots of x²+5x+6 are -2 and -3#
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