Answered

Ajay walks 7/8 of a km to school, while Sam walks 6/7 of a km to school. Who lives farther away from school?

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KAntoineDoixviz

✏️COMPARISON

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[tex] \large \bold{\blue{PROBLEM:}} [/tex] Ajay walks 7/8 of a km to school, while Sam walks 6/7 of a km to school. Who lives farther away from school?

[tex] \large \bold{\blue{SOLUTION:}} [/tex] Before we compare the two measurements, make sure the two fractions have the same denominator to indicate the new numerators which is higher and lower.

» Find the least common denominator of two fractions.

  • [tex] \Large \begin{array}{c|c} \sf \frac{7 \: × \:7}{8 \: × \: 7} & \sf \frac{6 \: × \: 8}{7 \: × \:8} \end{array} [/tex]

  • [tex] \Large \begin{array}{c|c} \sf \frac{49}{56} & \sf \frac{42}{56} \end{array} \\ [/tex]

» So, Ajay walks 49/56 km to school while Sam walks 42/56 km to school.

  • [tex] \sf \frac{49}{56} > \frac{42}{56} \\ [/tex]

[tex] \therefore \underline{\boxed{\tt \purple{Ajay \: lives \: farther \: away \: from \: school}}} [/tex]

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Donlenardfontelaviz

ANSWER:

Convert the two dissimilar fractions by finding the least common denominator.

[tex] \frac{7}{8}\times\frac{7}{7}= \frac{49}{56} \\ \\ \frac{6}{7} \: \times \frac{8}{8} \: = \frac{48}{56} [/tex]

[tex] \frac{49}{56} \: > \: \frac{48}{56} [/tex]

Ajay lives farther away from school.

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