Solving quadratic equation by completing the square:
x² + 5x- 10=0
please help me


Sagot :

x² +5x -10 = 0

x
² +5x = 10

x² +5x + [tex] \frac{25}{4} [/tex] = 10 - [tex] \frac{25}{4} [/tex]

[tex](x+ \frac{5}{2})^{2} = \frac{65}{4} [/tex]

x+ 5/2 = ± [tex] \sqrt{65}/4[/tex]

x = ± [tex] \sqrt{65}/4[/tex] -5/2

x = [tex] \frac{ \sqrt{65} -10 }{4} [/tex]   ;   x = [tex] \frac{- \sqrt{65} -10 }{4} [/tex]