Concept:-
We have to find the Circumference of the field for finding how much wire required.
We know
[tex]\boxed{\sf Circumference=2πr}[/tex]
[tex]\\ \sf\longmapsto Circumference=2\times \frac{22}{7}\times 5[/tex]
[tex]\\ \sf\longmapsto Circumference= \dfrac{44\times 5}{7}[/tex]
[tex]\\ \sf\longmapsto Circumference=\dfrac{220}{7}[/tex]
[tex]\\ \sf\longmapsto Circumference=31.4m[/tex]
She requires 31.4m wire