Answered

A diver shines a flashlight upward from beneath the water at a 35.2° angle to the vertical. At what angle does the light leave the water?

Sagot :

FierceFireflieeviz

Answer:-

  • sin i=35.2°
  • Refractive index of water=1.33
  • sin r=?

We know that

[tex]\boxed{\sf \mu=\dfrac{sin\:i}{sin\:r}}[/tex]

[tex]\sf\longmapsto 1.33=\dfrac{35.2}{sin\:r}[/tex]

[tex]\sf\longmapsto sin\:r=\dfrac{35.2}{1.33}[/tex]

[tex]\sf\longmapsto sin\:r=26.4°[/tex]

It will leave the water at a angle of 26.4°