what is the constant of the variation if a varies jointly as B and C, and A = 40 when B = 6 and C = 5
a. 600
b. 24
c. 4 over 3
d. 3 over 4​


Sagot :

Answer:

C. 4 over 3

Step-by-step explanation:

A varies jointly as B and C.

Therefore, A = kBC, from the original formula y = kxz

Given:

A = 40

B = 6

C = 5

constant of variation (k) = ?

Solution:

[tex]a = kbc[/tex]

[tex]40 = k(6)(5)[/tex]

[tex]40 = k(30)[/tex]

*divide 30 on both sides so that we can find the value of k (constant of variation)*

[tex] \frac{40}{30} = \frac{k(30)}{30} [/tex]

[tex] \frac{40}{30} = k[/tex]

*the lowest term of 40/30 is 4/3*

[tex] \frac{4}{3} = k[/tex]

The answer is C. 4 over 3