Crumplyvesselviz
Answered

Find the derivative of a function at x =0

f(x) = 3x³ + 2x² + 5x – 2​

Sagot :

Ethanzuaresviz

f(x) = 3x³+2x²-5x+6

=> f'(x) = d/dx( 3x³+2x²-5x+6)

= 9x²+4x-5

=> f'(2) = 9(2)²+4(2)-5

= 9×4+4×2-5

= 36+8-5

= 44-5

= 39