which equation can help us solve the distance of the observer and tha flagpole if the angle of elevation from the observer to a 14-foot flagpole is 60 degree
For this scenario, we will use the trigonometric ratio of Tangent,
let x = distance of the observer and the flagpole
This is the Trigonometric Ratio Equation to solve the distance x,
[tex]{\sf \tan\theta = \frac{opposite}{adjacent}}\\\\\sf where,\\\text {\sf $\theta = 60^\circ$}\\\text {\sf opposite = 14 ft (height of flagpole)}\\\text {\sf adjacent = x (distance between observer and flagpole)}[/tex]
Just to continue with our solution, let's solve for x,
[tex]\large {\sf \tan\theta = \frac{opposite}{adjacent}}\\\\\large {\sf tan60^\circ = \frac{14}{x}}\\\\\large {\sf x = \frac{14}{tan60^\circ}}\\\\\large {\sf x = 8.08 \;ft}\\\\[/tex]
[tex]\therefore \;\boxed{\text{\sf The distance between the observer and the flagpole is 8.08 ft}}[/tex]
* as always, double check my answers for errors or carelessness.
#No to copy paste solution
#No to plagiarism
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