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Answered

John owns a triangular piece of lot. If the sides of the lot are 11 m and 8 m, what must be the length of the longest side if the included angle measures 123°.​

Sagot :

Answer:

16.76m

Step-by-step explanation:

a = 11m

b = 8m

C = 123°

By law of cosines,

[tex]c=\sqrt{a^{2}+b^{2}-2abcos(C) } \\c=\sqrt{11^{2}+8^{2}-2(11)(8)cos(C) } \\c=16.76m[/tex]