Number 1.
The theoretical probability of a die showing a "3" is [tex]\frac{1}{6}[/tex].
Number 2.
The theoretical probability of a die showing an even number is [tex]\frac{3}{6} =\frac{1}{2}[/tex].
Number 3
The probability of a die showing an odd number is [tex]\frac{3}{6} =\frac{1}{2}[/tex].
Number 4
Based on the frequency of occurrences of numbers in a die, the probability that a die showing greater than 5 is [tex]\frac{14}{100}[/tex] = 0,14.
Number 5
The probability of a die showing " 2" is [tex]\frac{20}{100}[/tex] = 0,2.
Step-by-step explanation:
Be discovered:
The table shows the result of Michael rolling a die 100 times.
Outcome Frequency
1 16
2 20
3 22
4 10
5 18
6 14
Total 100
Question:
1. What is the theoretical probability of a die showing a "3"?
2. What is the theoretical probability of a die showing an even number?
3. In the experiment done by Michael, what is the probability of a die showing an odd number?
4. Based on the frequency of occurrences of numbers in a die, what is the probability that a die showing greater than 5?
5.When Michael rolled the die 100 times, what is the probability of a die showing " 2"?
Asked:
Number 1.
Sample point of throwing a die = 6
n(S) = 6
n(3) = 1
The theoretical probability of a die showing a "3" is [tex]\frac{1}{6}[/tex].
Number 2.
Sample point of throwing a die = 6
n(S) = 6
The even numbers on the die are 2, 4, 6.
Number of even numbers on the dice = 3
n(even) = 3
The theoretical probability of a die showing an even number is [tex]\frac{3}{6} =\frac{1}{2}[/tex].
Number 3
Sample point of throwing a die = 6
n(S) = 6
The odd numbers on the dice are 1, 3, 5.
Number of odd numbers on the dice = 3
n(odd) = 3
The probability of a die showing an odd number is [tex]\frac{3}{6} =\frac{1}{2}[/tex].
Number 4
Based on the frequency of occurrences of numbers in a die, the probability that a die showing greater than 5 is [tex]\frac{14}{100}[/tex] = 0,14.
Number 5
The probability of a die showing " 2" is [tex]\frac{20}{100}[/tex] = 0,2.
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