Answered

Subtract using the rule of groupings
(3x-2y+10)-(2x+y-2)

Sagot :

Palsme9971viz
(3x-2y+10) - (2x+y-2)

3x -2y+10 -2x -y+2 

3x-2x= x
-2y-y= -3y          combine like terms and apply the operation
10+2= 12

x-3y+12           final equation from the subtracted two equations
Chllviz
(3x-2y+10)-(2x+y-2)
1. Change the sign -(2x+y-2) = -2x-y+2

2. Combine like terms
3x-2y+10-2x-y+2=0
3x-2x-2y-y+10+2=0

3. Add
3x-2x-2y-y+10+2
x-3y+12

4. answer
x-3y+12