Answered

Limit of x - square root of x/ x - 16 as x approaches yo 16

Sagot :

Palsme9971viz
lim x= x²/x-16

x⇒16

vdu-udv/v² = x-16(2x)- (x²)(0)/ (x-16)²       ⇒ this formula is from the differentiation of                                                                  algebraic function

2x²-32x/(x-16)²

2(16)²- 32(16)/(16-16)²

undefined                    ⇒ final result