Answer:
V_{2} = 56.47mLV
2
=56.47mL
Explanation:
Use Charles's Law:
when Pressure is constant.
\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }
T
1
V
1
=
T
2
V
2
arrange:
V_{2} = \frac{V_{1}T_{2}}{T_{1}}V
2
=
T
1
V
1
T
2
GIVEN:
\begin{gathered}V_1 = 60mL\\T_1 = 33+273 = 306K\\T_2 = 15+273 = 288K\end{gathered}
V
1
=60mL
T
1
=33+273=306K
T
2
=15+273=288K
SOLUTION:
V_2=\frac{(60)(288)}{306}V
2
=
306
(60)(288)
V_2 = 56.47 mLV
2
=56.47ml
