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A 0.17 kg billiard cue ball moves forward at a velocity of 25m/s and hits the
other ball, 0.16
kg which is at rest. As a result of the collision, the cue ball moves
backward at 8m/s and the ball moves forward. What is the velocity of the other
ball after collision?​

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Answer:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i

Explanation:

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