Directions: Find out how much you already know about this lesson. Choose
the correct answer for each item. Write the letter of your answers on a
separate sheet of paper. Take note of the items that you have not answered
correctly and find out the right answer as you go through this module.
1. What is the angle formed by the horizontal line with the line of sight to an
object that is above the horizontal line?
A. Angle of elevation
B. Angle of depression
C. Both A and B
D. Neither Anor B
2. A building that is 40 m tall casts a shadow that is 48 m long. Find the angle
of elevation of the sun.
A. 56°
B. 390
C. 33°
D. 290
3. The angle of depression from the top of a lighthouse to a ship is 45°. If the
lighthouse is 20 m high, how far from the lighthouse is the ship?
A. 13 m
B. 17.23 m C. 18.20 m D. 20 m
4. A tower is 20.25 m high. At a certain distance away from the tower, an
observer determines that the angle of elevation to the top of it is 510. How far
is the observer from the base of the tower?
A. 16.40 m B. 13.46 m C. 10.87 m D. 7.89 m
5. An airplane is flying at a height of 6000 meters above the ground. The
distance along the ground from the airplane to the airport is 8000 meters.
What is the angle of depression from the airplane to the airport?
A. 24.230
B. 28.870
C. 36.870
D. 43.850​


Sagot :

1. What is the angle formed by the horizontal line with the line of sight to an object that is above the horizontal line?

A. Angle of elevation

B. Angle of depression

C. Both A and B

D. Neither A nor B

2. A building that is 40 m tall casts a shadow that is 48 m long. Find the angle of elevation of the sun.

A. 56°

B. 39°

C. 33°

D. 29°

Solution:

tanA = 40/48

A = arctan 0.8

A = 38.6598082540901

A = 39°

3. The angle of depression from the top of a lighthouse to a ship is 45°. If the lighthouse is 20 m high, how far from the lighthouse is the ship?

A. 13 m

B. 17.23 m

C. 18.20 m

D. 20 m

Solution:

tan45 = 20/x

x = 20/tan45

x = 20 m

4. A tower is 20.25 m high. At a certain distance away from the tower, an observer determines that the angle of elevation to the top of it is 51°. How far is the observer from the base of the tower?

A. 16.40 m

B. 13.46 m

C. 10.87 m

D. 7.89 m

Solution:

tan51 = 20.25/x

x = 20.25/tan51

x = 16.3981266722

x = 16.4 m

5. An airplane is flying at a height of 6000 meters above the ground. The distance along the ground from the airplane to the airport is 8000 meters. What is the angle of depression from the airplane to the airport?

A. 24.23°

B. 28.87°

C. 36.87°

D. 43.85°​

Solution:

tanA = 6000/8000

A = arctan 0.75

A = 36.869897645844

A = 36.87°

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