What is the molecular weight of a gas which diffuses 1/25 as fast as hydrogen?25
Solution:
Solution:1) Set rates and molecular weights:
Solution:1) Set rates and molecular weights:rate1 = unknown gas = 1
Solution:1) Set rates and molecular weights:rate1 = unknown gas = 1rate2 = H2 = 25
Remember, 1/25th of 25 is 1.
is 1.The molecular weight of H2 = 2.016
is 1.The molecular weight of H2 = 2.016The molecular weight of the other gas = x.
is 1.The molecular weight of H2 = 2.016The molecular weight of the other gas = x.2) By Graham's Law (see the solution to problem #1), we have:
is 1.The molecular weight of H2 = 2.016The molecular weight of the other gas = x.2) By Graham's Law (see the solution to problem #1), we have:1 / 25 = 2.016 / x
= 2.016 / x0.0004 = 2.016 / (x remember to square both sides)
x = 2520 g/molecular
