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A 9000-N automobile is pushed along a level road by four students who apply a total forward force of 500N. Neglecting friction, the acceleration of the automobile is: "

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Answer:

Given:

W = 9000 N

F = 500 N

Solution:

F = ma

m = W/g

F = (W/g)(a)

[tex]500 = ( \frac{9000}{9.81} )(a)[/tex]

[tex]a = 0.545 \: \frac{m}{ {s}^{2} } [/tex]