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what is [tex] 4^{x+1} / 2^{x+2} [/tex]

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Lhuckyviz
4^(x+1)=2^(x+2)
2^2(x+1)=2^(x+2)
the 2 will be cancelled out.. by using logarithmic..so,
2(x+1)=x+2
2x+2=x+2
x=0