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2x^2-3x-5=0 Using the quadratic formula

Sagot :

2x²-3x-5=0

x= -b±√(b²-4ac)
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2a
= -(-3)±√[(3²)-4(2)(-5)]
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2(2)
=3±√(9+40)
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4
=3±√49
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4
=3±7 = -4 or 10
----- = ---------
4 4

x= -1 or 2.5
Bardenbardenviz
2x2+2x−5x−5=0

2x(x+1)−5(x+1)=0

(x+1)(2x−5)=0

x=−1,5/2