Crystalxyrilviz
Answered

find the 9th term of the arithmetic sequence with a=10 and d=1/2

Sagot :

a=10
d=1/2
an=9

an=a+(n-1) d
an=10+(9-1)1/2
an=10+(8)1/2
an=10+4
an=6
Mizuviz
[tex] A_{n} = A_{1} + (n-1) (d) \\ A_{9} = 10 + (9-1) ( \frac{1}{2}) \\ A_{9}= 10 + (8) ( \frac{1}{2}) \\ A_{9}= 10 + 4 \\ A_{9}= 14[/tex]

--Mizu