Answered

how many terms are there in an arithmetic sequence with a common difference of 4 and with first and last terms 3 and 59,respectively?

Sagot :

formula: a sub n= a sub 1 + (n-1) d
answer:

59=3+(n-1)4
59=3+4n-4 (transpose +3 and -4)
59-3+4=4n
60=4n
(to eliminate 4 in 4n, divide both 60 and 4n by 4)
so...
60/4=4n/4
15=n
n=15
there are 15 terms...