Tletleviz
Answered

solve the quadratic equation 6(2x+1)²-40=56

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Betsparadaviz
6(2x+1)²-40=56= 6(4[tex] x^{2} [/tex]+2)-40=56
=16[tex] x^{2} [/tex]+12-40=56
=16x+12-40-56=0
16x+12-16=0

i just try to answer sorry if its wrong or not :)
Jeonelvieviz
6(2x+1)²-40=56 (2x+1)(2x+1)-40-56+6=0 4x²+2x+2x+1-40-56+6=0 4x²+4x-89=0