Answer:
The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.
Given;
the position of center of the target, x₀ = 60 m
initial velocity of the bullet, u = 240 m/s
The time the bullet strikes the center of the large target is calculated as;
The distance from the center of the target to the point where the bullet strikes the target is calculated as;
x = vt + ¹/₂gt²
where;
v is the final velocity of the bullet when it strikes the target = 0
x = 0 + ¹/₂(9.8)(0.25²)
x = 0.31 m
Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.
Read more on Brainly.com - https://brainly.com/question/20719306#readmore
Explanation:
I hope it helps