Sagot :
Answer:
The altitude of an equilateral triangle forms a 30-60-90 triangle with hypotenuse equal to one side of the original triangle. The altitude also bisects the base. Then the 30-60-90 triangle has long side (hypotenuse) of 12, short side ( half of the base) of 6. Let x = altitude.
Using Pythagoras theorem, 122 = 62 + x2
144 = 36 +x2
108 = x2 or x2 = (36)(3)
x = √(36)(3) = 6√3
QUESTION
the length of the side of an equilateral triangle is 12 cm find the length of its altitude?
ANSWER
- 10.4 centimeters
SOLUTION
So let's solve for h:
[tex]
\begin{gathered}c^2=a^2+b^2\\12^2=6^2+h^2\\144=36+h^2\\144-35=h^2\\108=h^2\\h=\sqrt{108} \\h=10.4\end{gathered}c2=a2+b2122=62+h2144=36+h2144−35=h2108=h2h=108h=10.4
[/tex]