Compute the number of sides of the given polygons given the sum of their interior angles.
1) 4680°
2) 9,900°


Sagot :

Compute the number of sides of the given polygons given the sum of their interior angles.

1) 4680° = 28 sides

  • 4640 ÷ 180° + 2
  • 26 + 2 = 28

Check

  • [tex] { \tt{= (n - 2) \times 180°}}[/tex]
  • [tex] { \tt{= ( \blue{28}- 2) \times 180°}}[/tex]
  • [tex] { \tt{= 26 \times 180°}}[/tex]
  • [tex]{ \green{ \tt{sum = 4,680 \degree}}}[/tex]

2) 9,900° = 57 sides

  • 9,900 ÷ 180° + 2
  • 55 + 2 = 57

Check

  • [tex] { \tt{= (n - 2) \times 180°}}[/tex]
  • [tex] { \tt{= ( \blue{57 } - 2) \times 180°}}[/tex]
  • [tex] { \tt{= 55 \times 180°}}[/tex]
  • [tex]{ \green { \tt{sum= 9,900°}}}[/tex]