Compute the number of sides of the given polygons given the sum of their interior angles.
1) 4680° = 28 sides
- 4640 ÷ 180° + 2
- 26 + 2 = 28
Check
- [tex] { \tt{= (n - 2) \times 180°}}[/tex]
- [tex] { \tt{= ( \blue{28}- 2) \times 180°}}[/tex]
- [tex] { \tt{= 26 \times 180°}}[/tex]
- [tex]{ \green{ \tt{sum = 4,680 \degree}}}[/tex]
2) 9,900° = 57 sides
- 9,900 ÷ 180° + 2
- 55 + 2 = 57
Check
- [tex] { \tt{= (n - 2) \times 180°}}[/tex]
- [tex] { \tt{= ( \blue{57 } - 2) \times 180°}}[/tex]
- [tex] { \tt{= 55 \times 180°}}[/tex]
- [tex]{ \green { \tt{sum= 9,900°}}}[/tex]